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所在平台: Udemy |
课程主页: https://www.udemy.com/course/transformer-differential-protection-calculations-p642-relay/
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课程名称：变压器差动保护计算 P642 继电器 课程概述：本课程专注于变压器的差动保护，这是任何变压器的主要保护手段。差动保护也被称为单元保护方案，仅在故障区域发生故障时才会动作，而在通过故障时则不应动作。 培训师介绍：课程培训师拥有超过21年的工作经验，涵盖了运营与维护、安装、测试、项目管理、咨询、监督、变电站自动化、SCADA和调试等多个领域。他的背景包括发电厂、高压变电站和高压直流（HVDC）安装，曾在西门子沙特阿拉伯等知名机构工作，参与了20多个变电站项目。他的专业知识涉及保护系统、变电站自动化系统、电源系统的设计、测试和调试、高压开关设备、保护继电器及控制方案。他在电气基础设施项目的测试与调试团队领导方面有着丰富的成功经验，服务于包括钢铁及石化行业在内的工业客户。 差动保护面临的实际挑战包括：变压器一次侧在次级开路时会带有无负载电流，导致保护方案不应动作的差动电流的产生；难以精确匹配CT比例，导致健康状况下的差动电流；在使用非标抽头的变压器时，由于基于特定抽头（标称抽头）计算的CT比例与不同抽头间的差异，甚至在健康状态下也会产生差动电流。为防止差动保护方案在这些条件下误动作，采用了百分比差动保护方案，虽然提高了安全性，但牺牲了灵敏度。在百分比差动保护中，给差动保护继电器提供了斜率特性。在现代数值差动保护继电器中，通常提供两个斜率。 课程内容包括对一台100MVA变压器的设置计算，相关数据如下： - 变压器额定容量：100 MVA - 高压侧电压：132 kV - 低压侧电压：33 kV - 电压组别：YNd1 - 阻抗：12.5% - 高压侧电流：437.4 A - 低压侧电流：1749.5 A - 抽头范围：±10% - 一次CT比率：500/1 A - 二次CT比率：1800/1 A 进一步计算内容包括：满载安培、短路MVA、高压和低压侧的短路电流、短路MVA与变压器百分比阻抗之间的关系、幅值和相位角误差及其补偿、CT误差及其补偿、工作电流和阻尼电流、动作电流计算、斜率1与2的计算、谐波阻塞计算及通过故障稳定性计算。 期待大家的参与。
Dear All,Differential protection is the main protection for any transformer. Differential protection is also called as unit protection scheme, it mean that it will operate in case of in zone fault and at through faults differential protection should not operate. Trainer Introduction:Your trainer brings over 21 years of experience in operation & maintenance, erection, testing, project management, consultancy, supervision, substation automation, SCADA, and commissioning. With a background spanning power plants, high voltage substations, and HVDC installations, he has worked with renowned organizations such as Siemens Saudi Arabia. He has been involved in over 20 high-voltage substation projects across Pakistan and Saudi Arabia.His expertise encompasses a wide range of areas including protection systems, substation automation systems, design, testing, and commissioning of power generation systems, high voltage switchgear, protection relays, and control schemes. He has a proven track record of leading testing and commissioning teams for implementing electrical infrastructure projects for industrial clients, including steel and petrochemical industries.A practical transformers and CTs pose some challenge to Differential Protection. They are as follows:The primary of transformer will carry no load current even when the secondary is open circuited. This will lead to differential current on which the protection scheme should not operate.It is not possible to exactly match the CT ratio as per equation. This would also lead to differential currents under healthy conditions.If the transformer is used with an off nominal tap, then differential currents will arise as the CT ratio calculated for a particular Tap (Nominal Tap) will be different for different Tap, even under healthy conditions.To prevent the Differential Protection scheme from picking up under such conditions, a Percentage Differential Protection scheme is used. It improves security at the cost of sensitivity.In Percentage Differential Protection, we provide a slope feature to the Differential Protection Relay. In modern Numerical Differential protection Relay two slopes are provided.In this course, we will perform the setting calculation of 100MVA transformer with following data:Transformer rating: 100 MVAHV side voltage: 132 kVLV side voltage: 33 kVVector group: YNd1Impedance: 12.5 %HV side current: 437.4 ALV side current: 1749.5 ATap range: ±10%Primary CT ratio: 500/1 ASecondary CT ratio: 1800/1 AFurther we will calculate: Full load amperesShort circuit MVAShort circuit current at HV & LV sidesrelationship between short circuit MVA and percentage impedance of transformerMagnitude and phase angle error and its compensationCT error and its compensationOperating and restraining currentsPickup current calculationsSlope 1 & 2 calculationsHarmonics blocking calculationsThrough fault stability calculationsBest Regards
